Calculate molarity and molality of sulphuric acid solution of density .g cm-3 containing 27% by mass of sulphuric acid (molar mass of H2SO4 = g mol-1)
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Calculate molarity and molality of sulphuric acid solution of density .g cm-3 containing 27% by mass of sulphuric acid (molar mass of
Answer:
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Answer:
Explanation: To calculate the molarity (
�
M) and molality (
�
m) of a solution, we need to use the following formulas:
�
�
�
�
�
�
�
�
(
�
)
=
Number of moles of solute
Volume of solution in liters
Molarity (M)=
Volume of solution in liters
Number of moles of solute
�
�
�
�
�
�
�
�
(
�
)
=
Number of moles of solute
Mass of solvent in kg
Molality (m)=
Mass of solvent in kg
Number of moles of solute
Given that the density of the solution is
�
�
/
�
�
3
D g/cm
3
and it contains
27
%
�
�
�
�
�
�
27% by mass of sulfuric acid (
�
2
�
�
4
H
2
SO
4
), we can find the molarity and molality.
Firstly, let's assume we have
100
�
100 g of the solution. Therefore, the mass of
�
2
�
�
4
H
2
SO
4
in this solution is
27
�
27 g (since it contains
27
%
�
�
�
�
�
�
27% by mass of
�
2
�
�
4
H
2
SO
4
).
Now, let's find the number of moles of
�
2
�
�
4
H
2
SO
4
:
Moles
=
Mass
Molar Mass
Moles=
Molar Mass
Mass
Moles
=
27
�
98
�
/
�
�
�
Moles=
98 g/mol
27 g
Next, we need to find the volume of the solution in liters. We know that
1
�
�
3
=
1
�
�
1 cm
3
=1 mL, so the volume in liters (
�
V) can be calculated using the density (
�
D):
�
=
Mass
Density
V=
Density
Mass
�
=
100
�
�
�
/
�
�
3
V=
D g/cm
3
100 g
Now, we can calculate the molarity:
�
=
Moles
�
M=
V
Moles
And the molality:
�
=
Moles
Mass of solvent (in kg)
m=
Mass of solvent (in kg)
Moles
You can substitute the values into these formulas to find the molarity and molality of the sulfuric acid solution.