calculate number of + and - ions from 95 gram of MgCl2.
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Answer:
95 g of [tex]MgCl_{2}[/tex] contains [tex]6.022 * 10^{23}[/tex] + ions and [tex]12.044 *10^{23}[/tex] - ions.
Explanation:
Given mass = 95 g
Molar mass of [tex]MgCl_{2}[/tex] = (1 * 24.3) + (2 * 35.5 )
= 95.2 g/mol ≈ 95 g/mol
Number of moles = given mass ÷ molar mass
= [tex]\frac{95}{95}[/tex]
= 1 mole
[tex]MgCl_{2}[/tex] → [tex]Mg^{+2} + 2Cl^{-1}[/tex]
1 mole contains [tex]6.022 * 10^{23}[/tex] particles
1 mole of [tex]MgCl_{2}[/tex] contains [tex]6.022 * 10^{23}[/tex] [tex]Mg^{+2}[/tex] ions
1 mole of [tex]MgCl_{2}[/tex] contains [tex]2*6.022 * 10^{23}[/tex] [tex]Cl^{-1}[/tex] ions
= [tex]12.044 *10^{23}[/tex] [tex]Cl^{-1}[/tex] ions
kindly refer the attachment...