Calculate the electrostatic field intensity on the axis of an circular disc having charge q.
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Calculate the electrostatic field intensity on the axis of an circular disc having charge q.
•Don't copy or spam, it's just waste of time.
#Revision_Q23
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Answer:
The diagram is :-
The electric field due to the ring an it &
axis at a distance x is given by:-
E=
(x
2
+R
2
)
3/2
kqx
To find maximum electric field, we will use the concept of maximum and minimum :-
dx
dE
=kq
(x
2
+R
2
)
(x
2
+R
2
)
3/2
−3/2(x
2
+R
2
)
1/2
.2x
2
Now,
dx
dE
=0⇒(x
2
+R
2
)
3/2
=
2
3
×2x
2
(x
2
+R
2
)
1/2
⇒x
2
+R
2
=3x
2
⇒2x
2
=R
2
⇒x
2
=
2
R
2
⇒x=±
2
R
So E
max
=
2
(
2
R
2
+R
2
)
3/2
k.q.R
=
3
3
R
3
k.q.2R
E
max
=
4πE
0
1
3
3
R
2
2q
Explanation:
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Refer The Attachment :)