Calculate the magnetic field due to a bar magnet of length 10cm and magnetic moment 10am^2 at a distance of 10cm on equatorial line
Share
Calculate the magnetic field due to a bar magnet of length 10cm and magnetic moment 10am^2 at a distance of 10cm on equatorial line
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Explanation:
Answer
Consider a point P located on the axial line of a short bar magnet of magnetic length 2l and strength M. Let us find B at a point P which is at a distance z from the centre of magnet. Magnetic flux density of P due to N-pole is
B1=4πμ0((z−l)2M) along NP
Similarly on S-Pole
B2=4πμ0(z+l)2M along SP
Net magnetic flux at P is
B=B1−B2=4πμ0[(z−l)2M−(z+l)2M]
=4πμ0[(z2−l2)24Mzl]
=4πμ0[(z2−l2)2M
have a wonderful day ahead
(•‿•)
Answer:
For a bar magnet, magnetic induction at a point on its axis is given by the formula,
B=4πμ0(d2+l2)3/2M
Where l is the length of bar magnet and d is distance of point from the centre of bar magnet. Hence, here, l=0.1 m and l=0.053 m.
Putting in the formula, we get B=10−4 T.