calculate the mass of CH3COONA required to make 500ml of 0.375molar aqueous solution. Given molar mass of CH3COONA=82mol
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calculate the mass of CH3COONA required to make 500ml of 0.375molar aqueous solution. Given molar mass of CH3COONA=82mol
Answer:
here's your answer dude
Answer:
Molarity = [tex]\frac{Moles}{Voume(L)}[/tex]
0.375 = [tex]\frac{Moles}{0.5L}[/tex]
∴ Moles = 0.1875
Moles = [tex]\frac{Mass}{82}[/tex]
= Moles × Molar mass = Given Mass
= 0.1875 × 82
∴ Given mass = 15.375 grams