calculate the mass of oxygen is required to completely burn two moles of methane
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calculate the mass of oxygen is required to completely burn two moles of methane
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Answer:
Explanation:
Balanced chemical equation for combustion of methane as follows.
CH
4
+2O
2
→CO
2
+2H
2
O
For 1 mole of combustion of methane 2 mole of oxygen are required.
48-gram methane =
16
48
=3 moles of methane.(Molecular weight of methane is 16)
So, no. of moles of oxygen required will be 6.