calculate the milli moles of Br2 produced when 10 ml of 0.1 molar (BrO3) minus reacts with excess of Br -
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calculate the milli moles of Br2 produced when 10 ml of 0.1 molar (BrO3) minus reacts with excess of Br -
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Answer: 3 milli moles of bromine gas is produced when 10 ml of 0.1 molar bromate ions reacts with excess of bromide ions.
Explanation:
Molarity of bromate ion = 0.1 M
According to reaction, the 1 mol of bromate ion gives 3 moles of bromine gas.
Then 0.001 moles of bromate ion will give:
of
Milli moles of =3 milli moles
3 milli moles of bromine gas is produced when 10 ml of 0.1 molar bromate ions reacts with excess of bromide ions.