calculate the mole fraction of benzene in solution containing 30 percent by mass in carbon tetra chloride
calculate the mole fraction of benzene in solution containing 30 percent by mass in carbon tetra chloride
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Hey !!
Let the mass of solution be 100 g
Mass of Benzene = 30 g
Mass of carbon tetrachloride = 100 g - 30 g = 770 g
Number of moles of benzene = Mass / Molar mass
= 30 g / 78 g mol⁻¹
= 0.385 mol
Number of moles of carbon tetrachloride = Mass / Molar mass
= 70 g / 154 g mol⁻¹
= 0.455 mol
Mole fraction of benzene = Mass of benzene / Moles of benzene + Moles of tetrachloride
= 0.385 mol / 0.840 mol
FINAL RESULT :- 0.458
Hope it helps you !!