calculate the number of chloride ions in 9.5 gram of magnesium chloride given the atomic mass of magnesium is 24 and chloride is 35.5
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calculate the number of chloride ions in 9.5 gram of magnesium chloride given the atomic mass of magnesium is 24 and chloride is 35.5
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no of moles = given mass / molar mass
molar mass of mgcl2 is mass of mg + mass of 2 cl atom
24 + 2*35.5 =94
given mass =9.5g
so, no of moles =9.5/94=19/188
no of ions = no of moles * avagadro no
19/188 * 6.022 *10
1 mole of mgcl2 = 24+2*35.5
= 24+71
= 95 g
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1 mole of mgcl2 contains 2 moles of Cl
mass of Cl in 1 mole of mgcl2 = 2*35.5= 71 g
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95 g mgcl2 contains 71g of cl
9.5 g mgcl2 contains 71/95*95/10= 7.1 g of Cl
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now,
35.5 g aluminium has ions 6.022*10^23
7.1 g aluminium has ions 6.022*10^23 *7.1/35.5
= 1.244*10^23 ions