Calculate the number of sodium ions that are present in 212g of sodium carbonate.
With explanation
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Calculate the number of sodium ions that are present in 212g of sodium carbonate.
With explanation
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Calculate the number of sodium ions that are present in 212g of sodium carbonate? Answer is 2.4092×10²⁴
Answer:
To find no of atoms present in a molecule, use the concept of atomicity.
no of atoms =atomicity×no of molecules ____(1)
step 1. find atomicity
atomicity of na ions in na2co3 =2
step 2. find no of molecules
as, 6.02×10²³ molecules= molar mass of that compound
molar mass of na2co3=(2×23)+(1×12)+(3×16) = 106g
then, 6.02×10²³ molecules=106g na2co3
for 212 g,
both sides×2,
212g of na2co3=12.04×10²³ molecules
from (1)_____ no of atoms of na in na2co3 is
2×12.04×10²³ atoms
= 24.08 ×10²³ atoms✌️✌️✌️✌️✌️