Calculate the pH of (a) 4.2 x 10 M H SO, b)
0.006M NaOH c) 9.2 ~ 10 4M HNO3.
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Calculate the pH of (a) 4.2 x 10 M H SO, b)
0.006M NaOH c) 9.2 ~ 10 4M HNO3.
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To find:
pH of
Calculation:
1) 4.2 × 10^(-4) M H2SO4
[tex]pH = - log \{{H}^{ + } \}[/tex]
[tex] = > pH = - log \{2 \times (4.2 \times {10}^{ - 4} ) \}[/tex]
[tex] = > pH = - log \{8.4 \times {10}^{ - 4} \}[/tex]
[tex] = > pH = 4 - log \{8.4 \}[/tex]
[tex] = > pH = 4 - 0.93[/tex]
[tex] \boxed{ = > pH = 3.07}[/tex]
2) 0.006 M NaOH
[tex]p(OH) = - log \{ {OH}^{ - 1} \}[/tex]
[tex] = > p(OH) = - log \{0.006 \}[/tex]
[tex] = > p(OH) = - log \{6 \times {10}^{ - 3} \}[/tex]
[tex] = > p(OH) = 3- log \{6 \}[/tex]
[tex] = > p(OH) = 2.22[/tex]
[tex] = > p(H) = 14 - 2.22[/tex]
[tex] \boxed{ = > p(H) = 11.77}[/tex]
3) 9.2 × 10^(-4) M HNO3:
[tex]pH = - log \{{H}^{ + } \}[/tex]
[tex] = > pH = - log \{9.2 \times {10}^{ - 4} \}[/tex]
[tex] = > pH = 4 - log \{9.2 \}[/tex]
[tex] = > pH = 4 - 0.96[/tex]
[tex] \boxed{ = > pH = 3.04}[/tex]
Hope It Helps.