Calculate the ratio of the frequencies of the radiation emitted due to transition of the electron in a hydrogen atom from its a) second primitive energy level to the first level and b) highest primitive energy level to the second primitive level
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Answer:
Energy of an electron in
n
t
h
permitted energy level is given by
E
n
t
h
=
−
13.6
n
2
e
−
V
.
(i) Energy of photon produced due to transition of an electron from second permitted energy level to the first level
E
=
E
2
−
E
1
E
=
−
13.6
(
2
)
2
(
−
13.6
1
2
)
e
V
=
10.2
e
V
(ii) Energy of photon produced due to transition of an electron from highest permitted energy level to the second permitted energy level.
E
'
E
∞
−
E
2
E
'
=
−
13.6
(
∞
)
2
−
(
−
13.6
2
2
)
⇒
E
'
=
13.6
4
=
3.4
Ratio of (i) and (ii)
E
E
'
=
10.2
3.4
=
3
Explanation:
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