Calculate the volume, mass and number of molecules of hydrogen liberated when 6.5grs of Zn reacts with 71grs of HCl at STP (atomic masses of Zn=65 U, Cl=35.5 U and H=1 U)
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Answer:
Explanation:
The volume of hydrogen gas liberated when 6.5 grams of zinc reacts with 71 grams of hydrochloric acid at standard temperature and pressure is 24.4 liters. The mass of hydrogen gas liberated is 0.48 grams. The number of molecules of hydrogen gas liberated is 2.7 x 10^24 molecules. In short, the answer is telling you that the volume of hydrogen gas that is produced when 6.5 grams of zinc reacts with 71 grams of hydrochloric acid is 24.4 liters. The mass of hydrogen gas that is produced is 0.48 grams. The number of molecules of hydrogen gas that is produced is 2.7 x 10^24 molecules.
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