calculate the volume occupied by 28 g nitrogen gas at STP
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Answer:
44.8 litre
Explanation:
Here moles of nitrogen=given mass /molar mass
=28/14
=2 moles
as we know one mole of any gas occupy 22.4 litre at STP
so 2 moles will occupy
=2×22.4
=44.8 litres
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