calculate ∆U,q and w when 2.0 mol of an ideal gas at 25°C are compressed isothermally and reversibly from 1.0bar to 10.0bar?
Share
calculate ∆U,q and w when 2.0 mol of an ideal gas at 25°C are compressed isothermally and reversibly from 1.0bar to 10.0bar?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
hope that this may helps u
Explanation:
Answer:
∆U = 0
q = -11411.69
w= 11411.69
Explanation:
n=2
P1 = 10
P2= 1
R = 8.314. ( constant value)
t = 25 + 273 K
= 298 K
w = 2.303nRt log P1/P2. ( using this formula)
w= 2.303×2×8.314×298×log 10/1
w= 11411.69×1. (log 10 = 1)
w = 11412. ( by round of)
∆U = 0. ( because temp is constant so ∆U =0)
∆U = q + w
0 = q + 11412
q = 0- 11412
q = -11412