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Answer:
Equivalent resistance between the points A and C
The resistance of AB and BC arm are in series so,
R
′
=2 Ω
Now this resistance is in parallel with the 2 Ω,
R
t
=
2+2
2×2
=1 Ω
ii ) Current in the circuit
I=
R
V
=
1
2
=2 A
iii ) Potential difference between A and B
As current divides equally, current in upper branch is 1 A,
so, Potential difference between AB is,
V=IR=1×1=1 V