can anyone solve the ii no. question answer please
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can anyone solve the ii no. question answer please
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Answer:
Given
Hypotenuse = 17,
one side =8,
By using Pythagoras theorem,
( Hypotenuse)2 = side 2+ side 2.
( 17 )2 =. ( 8 )2 + AC 2
289 = 64 + AC 2.
AC 2 = 289-64.
AC 2= 225
AC = √225 = 15
SO AC= 15
I HOPE IT WILL BE HELPS YOU TO UNDERSTAND.
PLEASE MARK AS BRAINLIEST
Step-by-step explanation:
Focus!
In the given triangle ABC,
AB = 8
BC = 17
AC² = AB² - BC² = 17² - 8²
AC² = 289 - 64 = 225
AC = √225
AC = 15
cosB = AB/BC = 8/17
So, cos²B = (8/17)² = 64/289
sinB = AC/BC = 15/17
sin²B = (15/17)² = 225/289
(ii) tanC = sinC /cosC
or tanC = AB/AC
tanC = 8/15
<hope you can do the rest. If not, feel free to ask.>
Thanks!