can someone pls give me the solution of this possess..... pls????
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can someone pls give me the solution of this possess..... pls????
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Given that : Numerator of fraction is 6 Less than the denominator of fraction .
So,
Numerator of fraction = ( X - 6 ).
Fraction = Numerator / Denominator = ( X - 6 ) / X.
Also given that : I f 3 is added to Numerator then fraction is equal to 2/3.
New Numerator = ( X - 6 + 3 ) = ( X - 3 ).
Denominator = X
New fraction = New Numerator / Denominator = ( X - 3 ) / X.
2/3 = ( X - 3 ) / X
2X = 3 ( X - 3 )
2X = 3X - 9
3X - 2X = 9
X = 9
Denominator of fraction = X = 9
And,
Numerator of fraction = X - 6 = 9 -6 = 3.
Fraction = Numerator/Denominator = 3/9 = 1/3.
So, original fraction = numerator / denominator
Given in the question that if 3 is added to the numerator of the original fraction, the new fraction becomes ( 2 / 3 ) ,
According to the question :
Hence,
Required original fraction = numerator / denominator
Required original fraction = ( x - 6 ) / ( x )