Can someone pls solve q.no. 2 for me....pls help me frnds...I need your help...plsssss
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Can someone pls solve q.no. 2 for me....pls help me frnds...I need your help...plsssss
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Therefore rate becomes (1.5)^2*3=6.75.
Hope my answer helps you
Please mark me as brainliest
Regards,
Adira.
R=k[A]^½[B]²
If concentration of A is increased 4 times then its final concentration is 4A and similarly final concentration of B is 2B.
so putting these values in rate equation we get
R'=k[4A]½[2B]²
or,R'=k x 2[A]^½ x 4[B]²
or,R'=8k[A]^½[B]²
or,R'=8R
so answer is C 8 times
Hope it helps.