D In trapezium ABCD. side AB | side CD diagonal AC and BD intersect each other at point P. Then prove
A(triangle ABP)/A(triangle CPD) =ABsquare / CD square
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D In trapezium ABCD. side AB | side CD diagonal AC and BD intersect each other at point P. Then prove
A(triangle ABP)/A(triangle CPD) =ABsquare / CD square
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