CENTRIPETAL ACCELERATION
A ball is whirled at the end of a string in a horizontal circle 60cm in radius at the rate of 1 revolution every 2s. Find the balls centripetal acceleration.
Share
CENTRIPETAL ACCELERATION
A ball is whirled at the end of a string in a horizontal circle 60cm in radius at the rate of 1 revolution every 2s. Find the balls centripetal acceleration.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Frequency f=2514Hz
Angular velocity ω=2πf=252×14πrad/s=3.52rad/s
Acceleration is a=ω2r=3.522×0.8=9.9m/s2
The direction is along the radius at every point towards the centre.
Given : A ball is whirled at the end of a string in a horizontal circle 60cm in radius at the rate of 1 revolution every 2s.
To find : centripetal acceleration of the ball.
solution : r = 60 cm = 0.6 m
The ball is whirled at the end of a string in a horizontal circle at the rate of one revolution every 2s.
so angular velocity, ω = angular displacement/time taken = 2π/2s = π rad/s
now centripetal acceleration, α = ω²r
= (π)² × 0.6
= 0.6π² m/s²
Therefore the centripetal acceleration of the ball is 0.6π² m/s²