Chap -6 Lines and angles ...... guys plz tell me the solution pf this question....
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Chap -6 Lines and angles ...... guys plz tell me the solution pf this question....
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Answer:
x = 115
Step-by-step explanation:
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Answer:
x = 125
Step-by-step explanation:
Triangle ABC=180°
Angle BAC + Angle ACB + Angle CBA = 180°
40° + 30° + Angle CBA =180°
Angle CBA = 180° - 70°
Angle CBA = 110°
Angle CBA + Angle EBD = 180°
110° + Angle EBD = 180°
Angle EBD = 180°- 110°
Angle EBD = 70°
Triangle EBD
Angle EBD + Angle EDB + Angle DEB = 180°
70° + 45° + Angle DEB = 180°
Angle DEB = 180° - 115°
Angle DEB = 55°
Angle DEB + Angle CED = 180°
55° + Angle CED = 180°
Angle CED = 180° - 55°
Angle CED = 125°
x = 125°