chapter5
exercise5.1 question1 part2
plz help me with this question.
Share
chapter5
exercise5.1 question1 part2
plz help me with this question.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
when 1/4 of the air is removed , then the
remaining air = 1 - 1/4 = 4-1/4 = 3/4
hope it helps you
have a nice day ahead ✌✌
Let the volume of air in a cylinder, initially, be V litres.
In each stroke, the vacuum pump removes 1/4th of air remaining in the cylinder at a time. Or we can say, after every stroke, 1-1/4 = 3/4th part of air will remain.
Therefore, volumes will be V, 3V/4 , (3V/4)² , (3V/4)³…and so on
Clearly, we can see here, the adjacent terms of this series do not have the common difference between them.
Therefore, this series is not an A.P.
This is the correct answer.
[tex]\huge{ son \: prodigal}[/tex]