Check whether 6 raise to N can end with the digit 0 for any natural number N ...
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Check whether 6 raise to N can end with the digit 0 for any natural number N ...
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so it will be divisibke by 5
which means 5 is one of the factor in its prime factorization which is not possible because 6raise to power n = (2×3) raise to power n
and it does not have 5 as a factor
It contradicts the uniqueness part of fundamental theorem of arithmetic
this contradiction has arisen due to our wrong supposition
hence 6 raise to power n cannot end with digit 0