CLASS 10
MATHS
TRIGNOMETRY...
1. Find the value to sin30° geometrically.
2. Find the value of 60° geometrically.
Answer this question by solving in copy....
THANKS...
☺☺✌✌✌
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CLASS 10
MATHS
TRIGNOMETRY...
1. Find the value to sin30° geometrically.
2. Find the value of 60° geometrically.
Answer this question by solving in copy....
THANKS...
☺☺✌✌✌
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For finding the value of sin 30° geometrically, we construct an equilateral triangle ABC of side 2 a. From A, we draw perpendicular AD to BC. Now, BD = CD = 1/2 BC = a
In triangle ABD, BAD + BDA + DAB = 180 (BY ANGLE SUM PROPERTY)
=> 60°+ BAD + 90°= 180° (SINCE AD | BC AND ALL ANGLES ARE 60° in a equilateral triangle)
=> BAD = 30°
IN RT TRIANGLE BAD,
SIN 30° = BD / AB= a / 2 a = 1/ 2
hence geometrically shown that sin 30 is 1/2
ABC in which perpendicular to AD .
BD = a and DC = a and AB = 2a.
Now in ∆ABD
AB^2 = Ad^2 + BD ^ 2
( 2a )^ 2 = AD ^ 2+ a ^2
4a^2 - a ^2 = AD ^2
3a ^2 = AD^2
√3a = AD
Then ,
sin 60= p/h
= √3a/ 2a
= √3/ 2
since , Sin60° = √3/2