Class:-9th (CBSE) (lesson no.6:- lines and angles)✨✨✨✨
Question:- In the given figure, m and n are two points plane mirror perpendicular to each other.Show that incident rays CA is parallel to reflected ray BD.
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Class:-9th (CBSE) (lesson no.6:- lines and angles)✨✨✨✨
Question:- In the given figure, m and n are two points plane mirror perpendicular to each other.Show that incident rays CA is parallel to reflected ray BD.
✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️
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Answer:
a force is a push or pull which is applied to the surface
Step-by-step explanation:
Given: Two plane mirrors m and n, perpendicular to each other. CA is incident ray and BD is reflected ray.
To Prove: CA∥DB
Construction: OA and OB are perpendiculars to m and n respectively.
Proof:
∵m⊥n,OA⊥m and OB⊥n
∴∠AOB=90
o
(Lines perpendicular to two perpendicular lines are also perpendicular.)
In ΔAOB,
∠AOB+∠OAB+∠OBA=180 degree
⇒90 degree
+∠2+∠3=180 degree
⇒∠2+∠3=90 degree
⇒2(∠2+∠3)=180 degree
(Multiplying both sides by 2)
⇒2(∠2)+2(∠3)=180 degree
⇒∠CAB+∠ABD=180 degree
(Angle of incidence = Angle of reflection)
∴∠1=∠2 and ∠3=∠4)
⇒CA∥BD (∠CAB & ∠ABD form a pair of consecutive interior angles and are supplementary)