consecutive numbers of an arithmetic sequence is k+1, 2k+1, 13. Then find the value of k?
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consecutive numbers of an arithmetic sequence is k+1, 2k+1, 13. Then find the value of k?
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Answer:
k = 4
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Verified answer
Since they are in AP....
Diffrence throughout is same....
So,
13-(2k+1) = (2k+1) - ( k+1)
[tex]13 - (2k + 1) = (2k + 1) - (k +1) \\ \\ 13 - 2k - 1 = 2k + 1 - k - 1 \\ \\ 12 - 2k = k \\ \\ 12 = 3k \\ \\ k = \frac{4}{1} [/tex]
k= 4