constant of a triangle stu in which angle t is equal to 60 degree angle u = 30 degree and P is equal to 7.5 CM
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constant of a triangle stu in which angle t is equal to 60 degree angle u = 30 degree and P is equal to 7.5 CM
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Answer:
Step-by-step explanation:
Let's assume that triangle STU is a scalene triangle (no sides are equal) and that you're given the following information:
Angle T = 60 degrees
Angle U = 30 degrees
Side TU = 7.5 cm (I assume you meant TU instead of P)
To find the remaining angles and side lengths, we can use the fact that the sum of the angles in any triangle is always 180 degrees.
Find Angle S:
Angle S = 180 - Angle T - Angle U
Angle S = 180 - 60 - 30
Angle S = 90 degrees
Now, you have all three angles of the triangle: Angle S = 90 degrees, Angle T = 60 degrees, and Angle U = 30 degrees.
Determine the type of triangle:
With one angle being 90 degrees, this triangle is a right-angled triangle.
Now, let's find the remaining side lengths using trigonometric ratios. Assuming TU is the hypotenuse, ST and SU are the legs.
a. For Angle T = 60 degrees:
Use the sine ratio: sin(T) = Opposite / Hypotenuse
sin(60) = ST / TU
ST = TU * sin(60)
b. For Angle U = 30 degrees:
Use the cosine ratio: cos(U) = Adjacent / Hypotenuse
cos(30) = SU / TU
SU = TU * cos(30)
Plug in the values and calculate the lengths:
ST = 7.5 * sin(60)
SU = 7.5 * cos(30)
You can use a calculator to find the numerical values for ST and SU.
Now you have the angles and side lengths for triangle STU with Angle T = 60 degrees, Angle U = 30 degrees, and TU = 7.5 cm.