Construct a ∆ABC such that AB = 6cm AC = 60° and BC = 5cm.
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Construct a ∆ABC such that AB = 6cm AC = 60° and BC = 5cm.
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Answer:
The ΔA
′
BC
′
whose sides are
4
3
of the corresponding sides of ΔABC can be drawn as follows:
Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60
∘
Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.
Step 3: Locate 4 points, B
1
,B
2
,B
3
,B
4
on line segment BX.
Step 4: Join B
4
C and draw a line through B
3
, parallel to B
4
C intersecting BC at C
′
.
Step 5: Draw a line through C
′
parallel to AC intersecting AB at A
′
.
The triangle A
′
BC
′
is the required triangle.
Answer:
The sum of the length of any two sides of a triangle must exceed than the length of the third side. ... So if AC - BC = 5cm so the property that the difference of the length of any two sides of triangle must be less than the length of the third side. So applying only this, we can construct a triangle, otherwise we cannot.