Construct a quadrilateral ABCD in which AB = 8.5cm, BC = 7.2cm, AD = 5cm, ∠B = 90° and ∠A = 30°.
Need steps of construction.
Thank you!
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Construct a quadrilateral ABCD in which AB = 8.5cm, BC = 7.2cm, AD = 5cm, ∠B = 90° and ∠A = 30°.
Need steps of construction.
Thank you!
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Hi Atlas , This is your solution!
Solution :
See the figure also for better understanding.
Steps :
1] Draw a line segment BC = 7.2 cm
2] With B as centre , Mark a Ray at 90°
3] with B as centre and radius 8.5 cm , draw an arc at the Ray cutting at 'A' . The line segment produced is AB .
4] With A as centre , Mark a Ray at 30° .
5] With A as centre and 5 cm as diameter, cut an arc at the Ray. Mark It as D . The line segment formed is AD
6] Join C and D .
7] The quadrilateral ABCD is produced !
Verified answer
Given:-
Quadrilateral ABCD..
Solution:-
Refer to attachment..
[tex] \textsf \red{Step \: of \: construction:}[/tex]
[tex] \sf \pink{Step \: 1:}[/tex] Draw line BC of 7.2 cm..
[tex] \sf \pink{Step \: 2:}[/tex]Take a protector and measure 90° at the point B
[tex] \sf \pink{Step \: 3:}[/tex]Now with point B draw a line of 8.5 cm and make a point A..
[tex] \sf \pink{Step \: 4:}[/tex]Now with the point A measure 30° with protector and at the point A draw a line of 5 cm..
[tex] \sf \pink{Step \: 5:}[/tex]Join line BA and AD and also join DC..
[tex] \sf \pink{Step \: 6:}[/tex]Hence Quadrilateral ABCD is formed..