construct a triangle pqr in which QR =6 CM angle Q = 60⁰ and PR – PQ = 2 cm.
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construct a triangle pqr in which QR =6 CM angle Q = 60⁰ and PR – PQ = 2 cm.
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[tex] \rm\large\dag\underline{ Question :-} \\ [/tex]
construct a triangle pqr in which QR =6 CM angle Q = 60⁰ and PR – PQ = 2 cm.
[tex] \\ \rm\large\dag\underline{ Solution :-} \\ [/tex]
Step 1 : - Draw a line Segment QR = 6 CM
Step 2 : - Draw a angel < Q = 60° at point Q and draw a ray QS .
Step 3 : - Cut a line Segment QT which is equal to PR - PQ = 2 CM ( PQ - PR = - 2 CM) .
QT will be below the line QR , because ( PQ - PR ) is negative .
Join RT
Step 4 : - Draw a Perpendicular Bisector of RT .
Step 5 : - PR, P is the point here perpendicular Bisector intersects QS .
Hence ∆ PQR is a required triangle .
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Step-by-step explanation:
Draw a line segment of base QR = 6 cm.
Measure and draw ∠Q = 60° and let the ray be QX.
Using a compass measure PR–PQ = 2cm.
As PR–PQ is negative, QD will below the line QR.
With Q as a centre and draw an arc at the point be D on the ray QX.
Join DR.