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Answer:
C) 15Ω is correct option
For a balanced wheatstone network,
[tex]\frac{R1}{R2}=\frac{R3}{R4}[/tex]
Here,
[tex]\frac{5}{10}=\frac{R'}{20}[/tex]
[tex]R'=10[/tex]
Since the two resistors are connected in parallel,
[tex]\frac{1}{R'}=\frac{1}{30}+\frac{1}{X}[/tex]
[tex]\frac{1}{10}-\frac{1}{30}=\frac{1}{X}[/tex]
[tex]\boxed{\boxed{X=15}}[/tex]
Hope this answer helped you :)
Answer:
Option C
Explanation: