cos A is equal to 2 by 3 then find the value of 2 tan square A + 9
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cos A is equal to 2 by 3 then find the value of 2 tan square A + 9
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Answer:
Step-by-step explanation:
Let theta be 'A'
Given=> cosA = 2/3
= base/hypotenous
Perpendicular = √(3)² - (2)²
= √9 - 4
= √5
secA = hypogenous/base = 3/2
tanA = perpendicular/base
= √5/2
So,
=> 2sec²A + 2tan²A - 9
=> 2(3/2)² + 2(√5/2)² - 9
=> (2×9)/4 + (2×5)/4 - 9
=> 9/2 + 5/2 - 9
=> (9 + 5)/2 - 9
=> 14/2 - 9
=> 7 - 9
=> -2. . Answer