cos60°/cos^245° -3 tan30°+5cos90°plss answer I will mark it as a brainliest
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cos60°/cos^245° -3 tan30°+5cos90°plss answer I will mark it as a brainliest
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Answer:
cos60°/cos.^2(45°)-3tan30°+5cos 90°
=(1/2)/(1/√2)^2-3(1/√3)+5(0)
=1-3/√3+0
=√3-3/√3
on multiplying by √3 in numerator and denominator, we get
=√3(√3-3)/√3(√3)
=(3-3√3)/3
=3(1-√3)/3
=1-√3
that's your answer