cosec2 (90°- theta) - tan2 theta/ 2 (cos2 48° + cos2 42°) - 2tan2 30° sec2 52° sin2 38°/cosec2 70°- tan2 20°
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Solution:
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We are using following :
i)
ii) We know the Trigonometric identity:
Sec²A - tan²A = 1
iii)
iv) sin²A + cos²A = 1
v) tan30° = 1/√3
vi) sec52° = sec(90-38) =cosec38°
vii ) cosecAsinA = 1
viii)cosec70= cosec(90-20)
= sec20°
ix ) cosec²A - cot²A = 1
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Now ,
LHS =
=
=
=
= $\frac{(3-4)}{6}$
= $\frac{-1}{6}$
Therefore,
= -1/6
••••
Step-by-step explanation:
here......
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