Could someone help me with this?
Pretty urgent!
Having my exam tomorrow!!!
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arc ABC subtends angle APC at circle and 100° at centre
so, angle APC=1/2 x 100 =50°
now PABC is a cyclic quadrilateral
so, angle APC+angleABC=180°
SO, angle ABC=180-50=130°
AND , angle ABC+angleCBD=180° as they are on straight line
so angle CBD = 180-130=50°
answer=50. for solution refer to image