could you please solve the question-
tan 1° tan 2° tan 3° ... tan 89°
I will mark best answer as brainliest.
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could you please solve the question-
tan 1° tan 2° tan 3° ... tan 89°
I will mark best answer as brainliest.
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tan1°tan2°tan3°.........tan89°
=tan1°.[cot1°]tan2°[cot2°]........tan45°
we know that tanθcotθ=1
so,
1×1×1×1×1×·············will be equal to 1
and the value of tan45°=1