Definite amount of gas occupied 500ml at 0°C and 4atm (Z=0.8). Calculate the volume occupied by the same amount of gas at 273°C and 1atm (Z=0.9).
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Definite amount of gas occupied 500ml at 0°C and 4atm (Z=0.8). Calculate the volume occupied by the same amount of gas at 273°C and 1atm (Z=0.9).
Andi Mandi sandi jo galat answer diya uski mummy***
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Answer:
138400.67 L
Explanation:
Bhai, main hamesha sahi jawab deta hu. Andi Mandi karne ki jarurat nahi hai.
To solve this problem, you can use the ideal gas law, assuming the gas behaves ideally. The ideal gas law is given as:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = universal gas constant
T = absolute temperature (in Kelvin)
First, you know the initial conditions:
P1 = 4 atm
V1 = 500 ml (which needs to be converted to liters, so V1 = 0.5 L)
Z1 = 0.8 (compressibility factor)
You don't know the number of moles (n) or R, but you can use the initial conditions to find nR:
nR = P1V1 / Z1 * T1
Now, convert the temperature from Celsius to Kelvin:
T1 = 0°C + 273.15 = 273.15 K
Now, calculate nR:
nR = (4 atm) * (0.5 L) / (0.8) * (273.15 K)
nR ≈ 273.93 atm L K^-1
Next, you want to find the final volume (V2) at different conditions:
P2 = 1 atm (final pressure)
T2 = 273°C + 273.15 = 546.15 K (final temperature)
Z2 = 0.9 (final compressibility factor)
Now, you can calculate V2 using the ideal gas law and nR:
V2 = nR * Z2 * T2 / P2
V2 = (273.93 atm L K^-1) * (0.9) * (546.15 K) / (1 atm)
V2 ≈ 138400.67 L
So, the volume occupied by the same amount of gas at 273°C and 1 atm is approximately 138400.67 liters.