Derive an expression for range of projectile and height of projectile in case of oblique projection.
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Derive an expression for range of projectile and height of projectile in case of oblique projection.
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Answer:
Thus, the maximum height of the projectile formula is, H = u 2 sin 2 θ 2 g . Q. Give the formulae for the time period, maximum height reached and range of a projectile motion.
Explanation:
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Answer:
Certainly! In the case of oblique projectile motion, you can derive expressions for the range and maximum height using the following equations. Let's assume the initial velocity of the projectile is "u," the angle of projection is "θ," the acceleration due to gravity is "g," the range is "R," and the maximum height is "H."
1. Range (R):
The range of a projectile is the horizontal distance it travels. You can find it using the formula:
R = (u^2 * sin(2θ)) / g
2. Maximum Height (H):
The maximum height reached by the projectile can be calculated using the formula:
H = (u^2 * (sin^2(θ))) / (2g)
These equations give you the range and maximum height of the projectile in oblique projection based on its initial velocity (u), the launch angle (θ), and the acceleration due to gravity (g).