Derive an expression for the potential energy of an elastic stretched spring.
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Derive an expression for the potential energy of an elastic stretched spring.
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Answer:
Hooke's Law, F = -kx, where F is the force and x is the elongation. The energy stored can be found from integrating by substituting for force, and we find, The energy stored = kx2/2, where x is the final elongation.
Explanation:
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Answer:-
Hooke's Law, F = -kx, where F is the force and x is the elongation. The energy stored can be found from integrating by substituting for force, and we find, The energy stored = kx2/2, where x is the final elongation.
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