Derive
the derivation of v = u + at!!
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Answer:
a = (v-u)/t. From this, v-u = at and v=u + at which proves the result. Representing v as a derivative, that is, v = ds/dt where s is the distance moved in time 't', and integrating w.r.t. 't' from 0 to t, one finds s = ut + (1/2)at^2. By eliminating 't' between this and v =u + at, one arrives at v^2 - u^2 = 2as.
Explanation:
.....hope it'll help u
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[tex]<body bgcolor=black><maquee direction="right"><font color=yellow>[/tex]
a = (V-U)/t
then
v-u = at
then...
v = u+at
[tex]<body bgcolor=blue><marquee direction="left" scrollamount=1300><font color=yellow>[/tex]
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