Derive the formula for the equivalent capacitance for a parallel combination of a number of Capacitors. plzzz give correct answer i need it for preparation of test
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Derive the formula for the equivalent capacitance for a parallel combination of a number of Capacitors. plzzz give correct answer i need it for preparation of test
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Answer:
In a parallel combination of capacitors, the capacitors are connected across a cell. Hence, the potential difference (V) across each each capacitor is the same. Let C1,C2,C3 be the capacitances of three capacitors connected in parallel and C be the equivalent capacitance of the combination.
Answer:
C=C1+C2+..+Cn
Explanation:
In a parallel combination of capacitors, the capacitors are connected across a cell. Hence, the potential difference (V) across each each capacitor is the same. Let C1,C2,C3 be the capacitances of three capacitors connected in parallel and C be the equivalent capacitance of the combination. The charge Q supplied by the cell is distributed as Q1,Q2andQ3 on the capacitors.
Since, capacitance =
C1=Q1/V, C2=Q2/V, C3=Q3/V and C=Q/V
∴Q1=C1V ,Q2=C2V, Q3=C3V and Q=CV
Now, Q=Q1+Q2+Q3
∴CV=C1V+C2V+C3V
∴C=C1+C2+C3
[Note: In general if n capacitors of capacitances C1,C2,...,Cn are connected in parallel, the equivalent capacitance of the equivalent capacitance of the combination is C=C1+C2+..+Cn]
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