determine the value of m, if (x+3) is a factor of x^3-3x^2-mx+24
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Answer:
m=10
Step-by-step explanation:
x+3 is a factor
Then -3 is a zero
f(-3)= (-3)³- 3(-3)²-m(-3)+24 =0
f(-3)= -27-27+24+3m=0
f(-3)= -30+3m=0
f(-3)= 3m=30
= m=10
Thus value of m is 10