Difference between area and perimeter of a square is 96. Find the length of diagonal of the square?
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Difference between area and perimeter of a square is 96. Find the length of diagonal of the square?
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Step-by-step explanation:
L×L-4L=96
[tex]L^{2}[/tex]-4L-96=0
L^2-12L+8L-96=0
L(L-12)+8(L-12)=0
(L+8)(L-12)=0
L=12
Diagonal=[tex]\sqrt{12^{2}+ 12^{2} }[/tex]
=12[tex]\sqrt{2}[/tex]