distance between p(0,5)q(2,0)
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Answer:
distance=√(x2-x1)2+(y2-y1)2
therefore,√(2-0)2+(0-5)2
=√4+25
=√29
Answer:
√29
Step-by-step explanation:
p(0,5)= x1=0 y1=5
q(2,0)= x2=2 ,y2=0
d(p,q)=√(x2-x2)²+(y2-y1)²
=√(2-0)²+(0-5)²
=√2²+(-5)²
=√4+25
=√29