Divide 534 into three parts such that the second part will be 32 less than twice the first, and the third will be 18 more than the first
Pleaseeeeeee solve this
I will mark you as brainliest
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Divide 534 into three parts such that the second part will be 32 less than twice the first, and the third will be 18 more than the first
Pleaseeeeeee solve this
I will mark you as brainliest
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Answer:
Let the first part be x
Then second part = 2x-32
Third part = x+18
Their sum = 534
x+2x-32+x+18 = 534
4x-14 = 534
4x = 534+14
4x = 548
x = 548/4
x = 137
First part = 137
Second part = 2(137)-32
= 274-32 = 242
Third part = 137+18 = 155