Divide 56 in four parts in A.P. such that the ratio of the product of their extremes (1 and 4th) to the
product of middle (2nd and 3rd) is 5:6
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Divide 56 in four parts in A.P. such that the ratio of the product of their extremes (1 and 4th) to the
product of middle (2nd and 3rd) is 5:6
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Answer:
Numbers are 8,12,16,20.
Step-by-step explanation:
Let the four parts be a−3d,a−d,a+d,a+3d
Sum, 4a=56
a=14
(a−d)(a+d)/(a−3d)(a+3d) = 5/6
6(a2−9d2)=5(a2−d2)
a2=49d2
d=±2
For d=2,
Numbers are 8,12,16,20.