divide 6x³+x²-26x-21 by 3x-7 and verify division algorithm
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divide 6x³+x²-26x-21 by 3x-7 and verify division algorithm
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Answer:
division algorithm-
D = d×Q +R
(dividend = divisor × quotient +remainder)
divisor = 3x-7
quotient = 2x² +5x+3
dividend = 6x³ +x²-26x-21
remainder = 0
D = (3x-7)(2x²+5x+3)+0
D = 3x(2x²+5x+3)-7(2x²+5x+3)
= 6x³+15x²+9x-14x²-35x-21
= 6x³ +x²-26x-21
6x³ +x²-26x-21 = 6x³ +x²-26x-21
L.H.S = R.H.S
hence verified.
* Note - For division refer the attachment.