Quality Question
@Differentiation
If , x = cos2\theta + 2cos\theta \ y = sin2\theta - 2sin\theta
x= cos2θ+2cosθ
y=sin2θ−2sinθ
the calculate dy/dx
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Quality Question
@Differentiation
If , x = cos2\theta + 2cos\theta \ y = sin2\theta - 2sin\theta
x= cos2θ+2cosθ
y=sin2θ−2sinθ
the calculate dy/dx
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x=cos2θ+2cosθ
=>dx/dθ= -2sin2θ-2sinθ
y=sin2θ-2sinθ
dy/dθ=2cos2θ-2cosθ
hance,
dy/dx= - (cos2θ-cosθ)/(sin2θ+sinθ)