if y=x^2-5x+7.then find Dy/ dx?
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Given that ,
The function is y = (x)² - 5x + 7
Differentiating with respect to x , we get
[tex] \sf \mapsto \frac{dy}{dx} = \frac{d \{ {(x)}^{2} - 5x + 7 \}}{dx} \\ \\ \sf \mapsto \frac{dy}{dx} =2x - 5 + 0 \\ \\ \sf \mapsto \frac{dy}{dx} =2x - 5[/tex]
[tex] \sf \large{ \underline{Remmember :-}}[/tex]
Power rule :
[tex] \sf \mapsto \frac{d {(x)}^{n} }{dx} = n {(x)}^{n - 1} [/tex]
Constant rule :
[tex] \sf \mapsto \frac{d(Constant)}{dx} = 0[/tex]
Given that ,
The function is y = (x)² - 5x + 7
Differentiating with respect to x ,
[tex]\sf \mapsto \frac{dy}{dx} = \frac{d \{ {(x)}^{2} - 5x + 7 \}}{dx}[/tex]
[tex]\sf \mapsto \frac{dy}{dx} =2x - 5 + 0[/tex]
[tex] \sf \mapsto \frac{dy}{dx} =2x - 5[/tex]
[tex]\sf \large{ \underline{Remmember :-}}[/tex]
Power rule :
[tex]\sf \mapsto \frac{d {(x)}^{n} }{dx} = n {(x)}^{n - 1}[/tex]
Constant rule :
[tex]\sf \mapsto \frac{d(Constant)}{dx} = 0[/tex]